The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

Question

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is (A) 225 J (B) 200 J (C) 400 J (D) 175 J

Tardigrade Admin · Accepted Answer

Word done W= Area A B C E F D A Area A B C D+ Area C E F D <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/83da294dbfd8c2e974dd419a6a329672-.png" /> =(1/2) ×(15+10) × 10+(1/2) ×(10+20) × 5 =125+75=200 J

Q. The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of $20 m$ is

225 J

200 J

400 J

175 J

Word done $W =$ Area $A BCEF D A$
Area $A BC D +$ Area $CEF D$

$= \frac{1}{2} \times (15 + 10) \times 10 + \frac{1}{2} \times (10 + 20) \times 5$
$= 125 + 75 = 200 J$

Q. The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20m is