The weight of a residue obtained by heating 2.76 g of silver carbonate is:

Question

The weight of a residue obtained by heating 2.76 g of silver carbonate is: (A) 2.76 g (B) 2.98 g (C) 2.16 g (D) 2.44 g

Tardigrade Admin · Accepted Answer

2 Ag 2 CO 3 xrightarrow textHeat4 Ag +2 CO 2+ O 2 2[(2 × 108)+12+48] 4 × 108 2(216+12+48) 4 × 108 2 × 276=552 4 × 108=432 ∵ 552 gm silver carbonate gives silver =432 g ∴ 2.76 g silver carbonate gives (432 × 2.76/552)=2.16 g

Q. The weight of a residue obtained by heating $2.76 g$ of silver carbonate is:

2.76 g

2.98 g

2.16 g

2.44 g

$2 A g_{2} C O_{3} Heat 4 A g + 2 C O_{2} + O_{2}$
$2 [(2 \times 108) + 12 + 48] 4 \times 108$
$2 (216 + 12 + 48) 4 \times 108$
$2 \times 276 = 5524 \times 108 = 432$
$∵ 552 g m$ silver carbonate gives silver
$= 432 g$
$∴ 2.76 g$ silver carbonate gives
$\frac{432 \times 2.76}{552} = 2.16 g$

Q. The weight of a residue obtained by heating 2.76g of silver carbonate is: