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Q. The weight of a residue obtained by heating $ 2.76\,g $ of silver carbonate is:

Punjab PMETPunjab PMET 2004Some Basic Concepts of Chemistry

Solution:

$2 Ag _{2} CO _{3} \xrightarrow{ \text{Heat}}4 Ag +2 CO _{2}+ O _{2}$
$2[(2 \times 108)+12+48] 4 \times 108$
$2(216+12+48) 4 \times 108$
$2 \times 276=552 4 \times 108=432$
$\because 552\, gm$ silver carbonate gives silver
$=432\, g$
$\therefore 2.76\, g$ silver carbonate gives
$\frac{432 \times 2.76}{552}=2.16\, g$