The weight of 350 mL of a diatomic gas at 0°C and 2 atm pressure is 1 g. The weight in g of one atom at NTP is:

Question

The weight of 350 mL of a diatomic gas at 0°C and 2 atm pressure is 1 g. The weight in g of one atom at NTP is: (A) 2.64 × 10-23 g (B) 2.64 × 10-22 g (C) 5.28 × 10-23 g (D) 0.82 × 10-22 g

Tardigrade Admin · Accepted Answer

PV (w/Mw) RT Mw=(wRT/PV) ⇒ (1×0.082×273/2×0.350) Mw=32

Q. The weight of $350 m L$ of a diatomic gas at $0^{\circ} C$ and $2 a t m$ pressure is $1 g$ . The weight in $g$ of one atom at $NTP$ is:

$2.64 \times 1 0^{- 23} g$

$2.64 \times 1 0^{- 22} g$

$5.28 \times 1 0^{- 23} g$

$0.82 \times 1 0^{- 22} g$

$P V \frac{w}{M _{w}} RT$
$M_{w} = \frac{wRT}{P V}$
$\Rightarrow \frac{1 \times 0.082 \times 273}{2 \times 0.350}$
$M_{w} = 32$

Q. The weight of 350mL of a diatomic gas at 0∘C and 2atm pressure is 1g. The weight in g of one atom at NTP is:

2.64×10−23g

2.64×10−22g

5.28×10−23g

0.82×10−22g