The wavelength of the de-Broglie wave associated with a thermal neutron of mass m at absolute temperature T is given by (Here, k is the Boltzmann constant)

Question

The wavelength of the de-Broglie wave associated with a thermal neutron of mass m at absolute temperature T is given by (Here, k is the Boltzmann constant) (A) (h/√2 m k T) (B) (h/√m k T) (C) (h/√3 k m T) (D) (h/2 √m k T)

Tardigrade Admin · Accepted Answer

KE of thermal neutron, (1/2)mv2=(3/2)kT or mv=√3 k m T ; So, λ =(h/p)=(h/√3 k m T)

Q. The wavelength of the de-Broglie wave associated with a thermal neutron of mass $m$ at absolute temperature $T$ is given by (Here, $k$ is the Boltzmann constant)

$\frac{h}{2 mk T}$

$\frac{h}{mk T}$

$\frac{h}{3 km T}$

$\frac{h}{2 mk T}$

KE of thermal neutron, $\frac{1}{2} m v^{2} = \frac{3}{2} k T$
or $m v = 3 km T$ ; So, $λ = \frac{h}{p} = \frac{h}{3 km T}$

Q. The wavelength of the de-Broglie wave associated with a thermal neutron of mass m at absolute temperature T is given by (Here, k is the Boltzmann constant)

2mkT​h​

mkT​h​

3kmT​h​

2mkT​h​

KE of thermal neutron, 21​mv2=23​kT or mv=3kmT​ ; So, λ=ph​=3kmT​h​

Q. The wavelength of the de-Broglie wave associated with a thermal neutron of mass $m$ at absolute temperature $T$ is given by (Here, $k$ is the Boltzmann constant)

$\frac{h}{2 mk T}$

$\frac{h}{mk T}$

$\frac{h}{3 km T}$

$\frac{h}{2 mk T}$

KE of thermal neutron, $\frac{1}{2} m v^{2} = \frac{3}{2} k T$
or $m v = 3 km T$ ; So, $λ = \frac{h}{p} = \frac{h}{3 km T}$