The wavelength (in mathringA) of a photon having energy 3 eV is approximately. [1 eV =1.6 × 10-12 erg ] [h=6.626 × 10-27 erg s ]

Question

The wavelength (in mathringA) of a photon having energy 3 eV is approximately. [1 eV =1.6 × 10-12 erg ] [h=6.626 × 10-27 erg s ] (A) 3000 (B) 4000 (C) 4141 (D) 7824

Tardigrade Admin · Accepted Answer

3 eV =3 × 1.6 × 10-12 erg = Energy (E) λ=(h c/E)=(6.626 × 10-27 × 3 × 108/3 × 1.6 × 10-12)=414 1 ( . mathringA)

Q. The wavelength (in $\overset{˚}{A}$ ) of a photon having energy $3 e V$ is approximately.
$[1 e V = 1.6 \times 1 0^{- 12} er g]$
$[h = 6.626 \times 1 0^{- 27} er g s]$

3000

4000

4141

7824

$3 e V = 3 \times 1.6 \times 1 0^{- 12}$ erg $=$ Energy $(E)$

$λ = \frac{h c}{E} = \frac{6.626 \times 1 0 ^{- 27} \times 3 \times 1 0 ^{8}}{3 \times 1.6 \times 1 0 ^{- 12}} = 4141$ ( $\overset{˚}{A})$

Q. The wavelength (in A˚) of a photon having energy 3eV is approximately. [1eV=1.6×10−12erg] [h=6.626×10−27ergs]