The wavelength associated with an electron accelerated through a potential difference of 100 V is of the order of:

Question

The wavelength associated with an electron accelerated through a potential difference of 100 V is of the order of: (A) 1.2 mathringA (B) 10.5 mathringA (C) 100 mathringA (D) 1000 mathringA

Tardigrade Admin · Accepted Answer

Here: Potentiel difference V=100 V We know that de Broglie wavelength of an electron is given by as λ =(h/√2 q V m) =(6.6 × 10-34/2 ×(1.6 × 10-19) × 100 × 9.1 × 10-31) =1.2 × 10-10 m =1.2 mathringA

Q. The wavelength associated with an electron accelerated through a potential difference of $100 V$ is of the order of:

$1.2 \overset{˚}{A}$

$10.5 \overset{˚}{A}$

$100 \overset{˚}{A}$

$1000 \overset{˚}{A}$

Here : Potentiel difference $V = 100 V$
We know that de Broglie wavelength of an electron is given by as
$λ = \frac{h}{2 q Vm}$
$= \frac{6.6 \times 1 0 ^{- 34}}{2 \times ( 1.6 \times 1 0 ^{- 19} ) \times 100 \times 9.1 \times 1 0 ^{- 31}}$
$= 1.2 \times 1 0^{- 10} m = 1.2 \overset{˚}{A}$

Q. The wavelength associated with an electron accelerated through a potential difference of 100V is of the order of:

1.2A˚

10.5A˚

100A˚

1000A˚