The wave function (in S I unit) for a light wave is given as Ψ(x, t)=103 sin π(3 × 106 x-9 × 1014 t) The frequency of the wave is equal to

Question

The wave function (in S I unit) for a light wave is given as Ψ(x, t)=103 sin π(3 × 106 x-9 × 1014 t) The frequency of the wave is equal to (A)  4.54× 1014Hz (B)  3.5× 1014Hz  (C)  3.5× 1010Hz  (D)  2.5× 1010Hz

Tardigrade Admin · Accepted Answer

The wave function Ψ(x, t)=103 sin π(3 × 106 x-9 × 104 t) Here, Angular frequency cos=9 × 1014 π ω=2 π n n=(ω/2 π)=(9 × 1014 π/2 π) =4.5 × 1014 Hz

Q. The wave function (in $S I$ unit) for a light wave is given as $Ψ (x, t) = 1 0^{3} sin π (3 \times 1 0^{6} x - 9 \times 1 0^{14} t)$ The frequency of the wave is equal to

$4.54 \times 1 0^{14} Hz$

$3.5 \times 1 0^{14} Hz$

$3.5 \times 1 0^{10} Hz$

$2.5 \times 1 0^{10} Hz$

The wave function
$Ψ (x, t) = 1 0^{3} sin π (3 \times 1 0^{6} x - 9 \times 1 0^{4} t)$
Here, Angular frequency $cos = 9 \times 1 0^{14} πω = 2 πn$
$n = \frac{ω}{2 π} = \frac{9 \times 1 0 ^{14} π}{2 π}$
$= 4.5 \times 1 0^{14} Hz$

Q. The wave function (in SI unit) for a light wave is given as Ψ(x,t)=103sinπ(3×106x−9×1014t) The frequency of the wave is equal to

4.54×1014Hz

3.5×1014Hz

3.5×1010Hz

2.5×1010Hz