The wave described by y = 0.25 sin( 10 π x - 2π t), where x and y are in meters and t in seconds, is a wave travelling along the

Question

The wave described by y = 0.25 sin( 10 π x - 2π t), where x and y are in meters and t in seconds, is a wave travelling along the (A) +ve x direction with frequency 1 Hz and wavelength λ = 0.2 m (B) -ve x direction with amplitude 0.25 m and wavelength λ = 0.2 m (C) -ve x direction with frequency 1 Hz (D) +ve x direction with frequency p Hz and wavelength λ = 0.2 m

Tardigrade Admin · Accepted Answer

y=0.25 sin (10 π x-2 π t) y max =0.25 k=(2 π/λ)=10 π ⇒ λ=0.2 m ω=2 π f=2 π ⇒ f=1 Hz The sign is negative inside the bracket. Therefore this wave travels in the positive x-direction.

Q. The wave described by $y = 0.25 sin (10 π x - 2 π t),$ where x and y are in meters and t in seconds, is a wave travelling along the

+ve x direction with frequency 1 Hz and wavelength $λ = 0.2 m$

-ve x direction with amplitude 0.25 m and wavelength $λ = 0.2 m$

-ve x direction with frequency 1 Hz

+ve x direction with frequency p Hz and wavelength $λ = 0.2 m$

$y = 0.25 sin (10 π x - 2 π t)$
$y_{m a x} = 0.25$
$k = \frac{2 π}{λ} = 10 π$
$\Rightarrow λ = 0.2 m$
$ω = 2 π f = 2 π$
$\Rightarrow f = 1 Hz$
The sign is negative inside the bracket.
Therefore this wave travels in the positive $x$ -direction.

Q. The wave described by y=0.25sin(10πx−2πt), where x and y are in meters and t in seconds, is a wave travelling along the

+ve x direction with frequency 1 Hz and wavelength λ=0.2m

-ve x direction with amplitude 0.25 m and wavelength λ=0.2m