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Physics
The wave described by y = 0.25 sin( 10 π x - 2π t), where x and y are in meters and t in seconds, is a wave travelling along the
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Q. The wave described by $y = 0.25 \sin( 10 \pi x - 2\pi t),$ where x and y are in meters and t in seconds, is a wave travelling along the
AIPMT
AIPMT 2008
Waves
A
+ve x direction with frequency 1 Hz and wavelength $\lambda = 0.2 m$
51%
B
-ve x direction with amplitude 0.25 m and wavelength $\lambda = 0.2 m$
27%
C
-ve x direction with frequency 1 Hz
11%
D
+ve x direction with frequency p Hz and wavelength $\lambda = 0.2 m$
11%
Solution:
$y=0.25 \sin (10 \pi x-2 \pi t) $
$y_{\max }=0.25 $
$k=\frac{2 \pi}{\lambda}=10 \pi$
$ \Rightarrow \lambda=0.2\, m$
$\omega=2 \pi f=2 \pi $
$\Rightarrow f=1 \,Hz$
The sign is negative inside the bracket.
Therefore this wave travels in the positive $x$-direction.