The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :

Question

The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is : (A) (88 RT / V ) (B) (3 RT / V ) (C) (5 RT /2) ( RT / V ) (D) (4 RT / V )

Tardigrade Admin · Accepted Answer

P V=(n1+n2+n3) R T P × V=[(16/32)+(28/28)+(44/44)] R T P V=[(1/2)+1+1] R T P=(5/2) (R T/V)

Q. The volume $V$ of an enclosure contains a mixture of three gases, $16 g$ of oxygen, $28 g$ of nitrogen and $44 g$ of carbon dioxide at absolute temperature T. Consider $R$ as universal gas constant. The pressure of the mixture of gases is :

$\frac{88 RT}{V}$

$\frac{3 RT}{V}$

$\frac{5 RT}{2} \frac{RT}{V}$

$\frac{4 RT}{V}$

$P V = (n_{1} + n_{2} + n_{3}) RT$
$P \times V = [\frac{16}{32} + \frac{28}{28} + \frac{44}{44}] RT$
$P V = [\frac{1}{2} + 1 + 1] RT$
$P = \frac{5}{2} \frac{RT}{V}$

Q. The volume V of an enclosure contains a mixture of three gases, 16g of oxygen, 28g of nitrogen and 44g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :

V88RT​

V3RT​

25RT​VRT​

V4RT​