Question

The volume of water to be added to $100c{m}^3$ of $0.5N{H}_{2}S{O}_4$ to get decinormal concentration is

• A. $400c{m}^3$
• B. $450c{m}^3$
• C. $500c{m}^3$
• D. $100c{m}^3$

Answer 1

Answer: (A)

$N_1{V}_1=N_2{V}_2$
or, $0.5\times 100=0.1\times V_2$
or, $V_2=\frac{0.5\times 100}{0.1}=500c{m}^3$
$\therefore (500-100)=400c{m}^3$ water is to be added to $100c{m}^3$ of $0.5N{H}_{2}S{O}_4$