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IIT JEEIIT JEE 2008The Solid State
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Solution:
In close packed arrangement, side of the base =2r ⇒RS=r
Also MNR is equilateral triangle, ∠PRS=30∘
In triangle PRS,cos30∘=PRRS=23 ⇒PR=32RS=32r
In right angle triangle PQR:PQ=QR2−PR2=232r ⇒ Height of hexagon =2PQ=432r ⇒ Volume = Area of base × height =643(2r)2×432r =242r3