The volume of oxygen necessary for the complete combustion of 20 L of propane is :

Question

The volume of oxygen necessary for the complete combustion of 20 L of propane is : (A) 40 L (B) 60 L (C) 80 L (D) 100 L

Tardigrade Admin · Accepted Answer

Combustion of propane takes place as follows: underset textPropane mathopC3H8 + underset textOxygen mathop5O2 xrightarrow3CO2+4H2O ∵ 1 L of propane required 5L of oxygen for combustion. ∴ 20 L of propane required oxygen = text 5× 20 text =100 text L.

Q. The volume of oxygen necessary for the complete combustion of 20 L of propane is :

40 L

60 L

80 L

100 L

Combustion of propane takes place as follows: $Propane C_{3} H_{8} + Oxygen 5 O_{2} 3 C O_{2} + 4 H_{2} O$ $∵$ 1 L of propane required 5L of oxygen for combustion. $∴$ 20 L of propane required oxygen $= 5 \times 20 = 100 L .$

Q. The volume of oxygen necessary for the complete combustion of 20 L of propane is :

40 L

60 L

80 L

100 L

Combustion of propane takes place as follows: PropaneC3​H8​​+Oxygen5O2​​​3CO2​+4H2​O ∵ 1 L of propane required 5L of oxygen for combustion. ∴ 20 L of propane required oxygen =5×20=100L.

Combustion of propane takes place as follows: $Propane C_{3} H_{8} + Oxygen 5 O_{2} 3 C O_{2} + 4 H_{2} O$ $∵$ 1 L of propane required 5L of oxygen for combustion. $∴$ 20 L of propane required oxygen $= 5 \times 20 = 100 L .$