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  4. The volume of oxygen necessary for the complete combustion of 20 L of propane is :

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Q. The volume of oxygen necessary for the complete combustion of 20 L of propane is :

WBJEEWBJEE 2006

Solution:

Combustion of propane takes place as follows: $ \underset{\text{Propane}}{\mathop{{{C}_{3}}{{H}_{8}}}}\,+\underset{\text{Oxygen}}{\mathop{5{{O}_{2}}}}\,\xrightarrow{{}}3C{{O}_{2}}+4{{H}_{2}}O $ $ \because $ 1 L of propane required 5L of oxygen for combustion. $ \therefore $ 20 L of propane required oxygen $ =\text{ }5\times 20\text{ }=100\text{ }L. $