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Question
Chemistry
The volume of oxygen necessary for the complete combustion of 20 L of propane is:
Q. The volume of oxygen necessary for the complete combustion of
20
L
of propane is:
1776
222
Rajasthan PMT
Rajasthan PMT 2006
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A
40 L
B
60 L
C
80 L
D
100 L
Solution:
Combustion of propane takes place as follows:
Propane
C
3
H
O
+
oxygen
5
O
2
⟶
3
C
O
2
+
4
H
2
O
∵
1
L
of propane required
5
L
of oxygen for combustion.
∴
20
L
of propane required oxygen
=
5
×
20
=
100
L