The volume of oxygen liberated at STP from 15 mL of 20 volume H2O2 is

Question

The volume of oxygen liberated at STP from 15 mL of 20 volume H2O2 is (A) 100 mL (B) 150 mL (C) 200 mL (D) 250 mL

Tardigrade Admin · Accepted Answer

20 -vol H 2 O 2 means 1 mL of H 2 O 2 of 20 volume gives =20 mL of O 2 at STP. Thus, 15 mL of H 2 O 2 of 20 volume gives =15 × 20 mL of O 2 at STP Volume of O2 at STP =300 mL

Q. The volume of oxygen liberated at $STP$ from $15 m L$ of $20$ volume $H_{2} O_{2}$ is

100 mL

150 mL

200 mL

250 mL

300 mL

$20$ -vol $H_{2} O_{2}$ means

$1 m L$ of $H_{2} O_{2}$ of $20$ volume gives $= 20 m L$ of $O_{2}$ at $STP$ .

Thus, $15 m L$ of $H_{2} O_{2}$ of $20$ volume gives $= 15 \times 20 m L$ of $O_{2}$ at $STP$

Volume of $O_{2}$ at $STP = 300 m L$

Q. The volume of oxygen liberated at STP from 15mL of 20 volume H2​O2​ is