The volume of one mole of an ideal gas changes from V to 2 V at temperature 300 K. If R is universal gas constant, then work done in this process is

Question

The volume of one mole of an ideal gas changes from V to 2 V at temperature 300 K. If R is universal gas constant, then work done in this process is (A) 300 R ln 2 (B) 600 Rln 2 (C) 300 ln 2 (D) 600 ln 2

Tardigrade Admin · Accepted Answer

Work done in an isothermal process W=n R T ln ((V2/V1)) Here, n=1 mol, T=300 K , V1=V and V2=2 V ∴ W=1 × R × 300 ln ((2 V/V)) =300 R ln 2

Q. The volume of one mole of an ideal gas changes from $V$ to $2 V$ at temperature $300 K$ . If $R$ is universal gas constant, then work done in this process is

$300 R ln 2$

$600 Rl n 2$

$300 ln 2$

$600 ln 2$

Work done in an isothermal process
$W = n RT ln (\frac{V _{2}}{V _{1}})$
Here, $n = 1$ mol, $T = 300 K$ ,
$V_{1} = V$ and $V_{2} = 2 V$
$∴ W = 1 \times R \times 300 ln (\frac{2 V}{V})$
$= 300 R ln 2$

Q. The volume of one mole of an ideal gas changes from V to 2V at temperature 300K. If R is universal gas constant, then work done in this process is

300Rln2

600Rln2

300ln2

600ln2