The volume of a sphere is given by V=(4/3) π r3. Make r as the subject of the formula.

Question

The volume of a sphere is given by V=(4/3) π r3. Make r as the subject of the formula. (A) √(3 V/4 π) (B) (3 V/4 π) (C) ((3 V/π))(1/3) (D) ((3 V/4 π))(1/3)

Tardigrade Admin · Accepted Answer

(i) Apply transposition. (ii) Cross multiply and then write r3 on LHS remaining on RHS. (iii) Apply cube root on both the sides.

Q. The volume of a sphere is given by $V = \frac{4}{3} π r^{3}$ . Make $r$ as the subject of the formula.

$\frac{3 V}{4 π}$

$\frac{3 V}{4 π}$

$(\frac{3 V}{π})^{\frac{1}{3}}$

$(\frac{3 V}{4 π})^{\frac{1}{3}}$

(i) Apply transposition.
(ii) Cross multiply and then write $r^{3}$ on LHS remaining on RHS.
(iii) Apply cube root on both the sides.

Q. The volume of a sphere is given by V=34​πr3. Make r as the subject of the formula.

4π3V​​

4π3V​

(π3V​)31​

(4π3V​)31​

(i) Apply transposition. (ii) Cross multiply and then write r3 on LHS remaining on RHS. (iii) Apply cube root on both the sides.

Q. The volume of a sphere is given by $V = \frac{4}{3} π r^{3}$ . Make $r$ as the subject of the formula.

$\frac{3 V}{4 π}$

$\frac{3 V}{4 π}$

$(\frac{3 V}{π})^{\frac{1}{3}}$

$(\frac{3 V}{4 π})^{\frac{1}{3}}$

(i) Apply transposition.
(ii) Cross multiply and then write $r^{3}$ on LHS remaining on RHS.
(iii) Apply cube root on both the sides.