The volume of a certain mass of gas at constant pressure is doubled to its value at 0° C . The temperature of the gas will be,

Question

The volume of a certain mass of gas at constant pressure is doubled to its value at 0° C . The temperature of the gas will be, (A) 100° C (B) 173° C (C) 273° C (D) 546° C

Tardigrade Admin · Accepted Answer

According to Charle's law, (V/273 K)=(2 V/ T)⇒ T=546K ⇒ T=546-273=273° C .

Q. The volume of a certain mass of gas at constant pressure is doubled to its value at $0^{\circ} C$ . The temperature of the gas will be,

$10 0^{\circ} C$

$17 3^{\circ} C$

$27 3^{\circ} C$

$54 6^{\circ} C$

According to Charle's law,
$\frac{V}{273 K} = \frac{2 V}{T} \Rightarrow T = 546 K$
$\Rightarrow T = 546 - 273 = 27 3^{\circ} C$ .

Q. The volume of a certain mass of gas at constant pressure is doubled to its value at 0∘C . The temperature of the gas will be,

100∘C

173∘C

273∘C

546∘C