The volume of 10 N and 4 N HCl required to make 1 litre of 7 N HCl are

Question

The volume of 10 N and 4 N HCl required to make 1 litre of 7 N HCl are (A) 0.75 litre of 10 N HCl and 0.25 litre of 4 N HCl (B) 0.80 litre of 10 N HCl and 0.20 litre of 4 N HCl (C) 0.60 litre of 10 N HCl and 0.40 litre of 4 N HCl (D) 0.50 litre of 10 N HCl and 0.50 litre of 4 N HCl

Tardigrade Admin · Accepted Answer

Let V litre of 10 N HCI be mixed with (1-V) litre of 4 N HCl to give (V+1-V)=1 L of 7 N HCl N1 V1+N2 V2 =NV 10 V+4(1-V) =7 × 1 10 V+4-4 V =7 6 V =7-4 V =(3/6)=0.50 L Volume of 10 N HCI =0.50 L Volume of 4 N HCl =1-0.50 =0.50 L

Q. The volume of $10 N$ and $4 N H Cl$ required to make $1$ litre of $7 N H Cl$ are

$0.75$ litre of $10 N H Cl$ and $0.25$ litre of $4 N H Cl$

$0.80$ litre of $10 N H Cl$ and $0.20$ litre of $4 N H Cl$

$0.60$ litre of $10 N H Cl$ and $0.40$ litre of $4 N H Cl$

$0.50$ litre of $10 N H Cl$ and $0.50$ litre of $4 N H Cl$

Q. The volume of 10N and 4NHCl required to make 1 litre of 7NHCl are

0.75 litre of 10NHCl and 0.25 litre of 4NHCl

0.80 litre of 10NHCl and 0.20 litre of 4NHCl

0.60 litre of 10NHCl and 0.40 litre of 4NHCl

0.50 litre of 10NHCl and 0.50 litre of 4NHCl

Let V litre of 10NHCI be mixed with (1−V) litre of 4 NHCl to give (V+1−V)=1L of 7NHCl N1​V1​+N2​V2​=NV 10V+4(1−V)=7×1 10V+4−4V=7 6V=7−4 V=63​=0.50L Volume of 10NHCI=0.50L Volume of 4NHCl=1−0.50=0.50L

Q. The volume of $10 N$ and $4 N H Cl$ required to make $1$ litre of $7 N H Cl$ are

$0.75$ litre of $10 N H Cl$ and $0.25$ litre of $4 N H Cl$

$0.80$ litre of $10 N H Cl$ and $0.20$ litre of $4 N H Cl$

$0.60$ litre of $10 N H Cl$ and $0.40$ litre of $4 N H Cl$

$0.50$ litre of $10 N H Cl$ and $0.50$ litre of $4 N H Cl$