The volume of 10 N and 4 N HCl required to make 1 L of 7 N HCl are

Question

The volume of 10 N and 4 N HCl required to make 1 L of 7 N HCl are (A) 0.50 L of 10 N HCl and 0.50 L of 4 N HCl (B) 0. 60 L of 10 N HCl and 0.40 L of 4 N HCl (C) 0.80 L of 10 N HCl and 0.20 L of 4 N HCl (D) 0.75 L of 10 N HCl and 0.25 L of 4 N HCl

Tardigrade Admin · Accepted Answer

Let V litre of 10 N HCl be mixed with (1-V) litre of 4 N HCl to give (V+1-V)=1 L of 7 N HCl. From, N1 V1+N2 V2 =N V 10 V+4(1-V) =7 × 1 10 V+4-4 V =7 6 V =7-4 V =(3/6)=0.50 L Volume of 10 N HCl =0.50 L Volume of 4 N HCl =1-0.50=0.50 L

Q. The volume of 10N and 4NHCl required to make 1L of 7NHCl are

0.50 L of 10 N HCl and 0.50 L of 4 N HCl

0. 60 L of 10 N HCl and 0.40 L of 4 N HCl

0.80 L of 10 N HCl and 0.20 L of 4 N HCl

0.75 L of 10 N HCl and 0.25 L of 4 N HCl

Let V litre of 10NHCl be mixed with (1−V) litre of 4NHCl to give (V+1−V)=1L of 7NHCl. From, N1​V1​+N2​V2​=NV 10V+4(1−V)=7×1 10V+4−4V=7 6V=7−4 V=63​=0.50L Volume of 10NHCl=0.50L Volume of 4NHCl=1−0.50=0.50L

Q. The volume of $10 N$ and $4 N H Cl$ required to make $1 L$ of $7 N H Cl$ are