The volume occupied by an atom is greater than the volume of the nucleus by factor of about

Question

The volume occupied by an atom is greater than the volume of the nucleus by factor of about (A) 1010 (B) 1015 (C) 101 (D) 105

Tardigrade Admin · Accepted Answer

Radius of atom ≈ 10-10 m Radius of nucleus ≈ 10-15 m Required ratio =( text volume of atom / text volume of nucleus ) =((4/3) π r13/(4)3 π r23) =((10-10/10-15))3 =1015

Q. The volume occupied by an atom is greater than the volume of the nucleus by factor of about

$1 0^{10}$

$1 0^{15}$

$1 0^{1}$

$1 0^{5}$

Radius of atom $\approx 1 0^{- 10} m$
Radius of nucleus $\approx 1 0^{- 15} m$
Required ratio $= \frac{volume of atom}{volume of nucleus}$
$= \frac{\frac{4}{3} π r _{1}^{3}}{\frac{4}{3} π r _{2}^{3}}$
$= (\frac{1 0 ^{- 10}}{1 0 ^{- 15}})^{3}$
$= 1 0^{15}$

Q. The volume occupied by an atom is greater than the volume of the nucleus by factor of about

1010

1015

101

105

Radius of atom ≈10−10m Radius of nucleus ≈10−15m Required ratio = volume of nucleus volume of atom ​ =34​πr23​34​πr13​​ =(10−1510−10​)3 =1015

$1 0^{10}$

$1 0^{15}$

$1 0^{1}$

$1 0^{5}$

Radius of atom $\approx 1 0^{- 10} m$
Radius of nucleus $\approx 1 0^{- 15} m$
Required ratio $= \frac{volume of atom}{volume of nucleus}$
$= \frac{\frac{4}{3} π r _{1}^{3}}{\frac{4}{3} π r _{2}^{3}}$
$= (\frac{1 0 ^{- 10}}{1 0 ^{- 15}})^{3}$
$= 1 0^{15}$