The volume occupied by 1 mole atom of a diatomic gas at STP is

Question

The volume occupied by 1 mole atom of a diatomic gas at STP is (A) 22.4 L (B) 11.2 L (C) 5.6 L (D) 44.8 L

Tardigrade Admin · Accepted Answer

1 mole of a diatomic gas contains 2 moles of atom ( H 2. contains 2 moles of H -atom) and occupies 22.4 L of volume. Hence volume occupied by 1 mole of atom of diatomic gas is (22.4/2) L i.e. 11.2 L.

Q. The volume occupied by 1 mole atom of a diatomic gas at STP is

22.4 L

11.2 L

5.6 L

44.8 L

$1$ mole of a diatomic gas contains $2$ moles of atom $(H_{2}$ contains 2 moles of $H$ -atom) and occupies $22.4 L$ of volume. Hence volume occupied by 1 mole of atom of diatomic gas is $\frac{22.4}{2} L$ i.e. $11.2 L$ .

Q. The volume occupied by 1 mole atom of a diatomic gas at STP is

22.4 L

11.2 L

5.6 L

44.8 L

1 mole of a diatomic gas contains 2 moles of atom (H2​ contains 2 moles of H -atom) and occupies 22.4L of volume. Hence volume occupied by 1 mole of atom of diatomic gas is 222.4​L i.e. 11.2L.

$1$ mole of a diatomic gas contains $2$ moles of atom $(H_{2}$ contains 2 moles of $H$ -atom) and occupies $22.4 L$ of volume. Hence volume occupied by 1 mole of atom of diatomic gas is $\frac{22.4}{2} L$ i.e. $11.2 L$ .