The vertical component of the earth's magnetic field is 6 × 10-5 T at any place where the angle of dip is 37°. The earth's resultant magnetic field at that place will be (. Given tan 37°=(3/4) )

Question

The vertical component of the earth's magnetic field is 6 × 10-5 T at any place where the angle of dip is 37°. The earth's resultant magnetic field at that place will be (. Given tan 37°=(3/4) ) (A) 8 × 10-5 T (B) 6 × 10-5 T (C) 5 × 10-4 T (D) 1 × 10-4 T

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/4af096845324eed58e4d846b28a5eac8-.png" /> (δ=37°) B V = B sin δ 6 × 10-5= B (3/5) B =10 × 10-5 T =10-4 T

Q. The vertical component of the earth's magnetic field is $6 \times 1 0^{- 5} T$ at any place where the angle of dip is $3 7^{\circ}$ . The earth's resultant magnetic field at that place will be $($ Given $tan 3 7^{\circ} = \frac{3}{4}$ )

$8 \times 1 0^{- 5} T$

$6 \times 1 0^{- 5} T$

$5 \times 1 0^{- 4} T$

$1 \times 1 0^{- 4} T$

$(δ = 3 7^{\circ})$
$B_{V} = B sin δ$
$6 \times 1 0^{- 5} = B \frac{3}{5}$
$B = 10 \times 1 0^{- 5} T$
$= 1 0^{- 4} T$

Q. The vertical component of the earth's magnetic field is 6×10−5T at any place where the angle of dip is 37∘. The earth's resultant magnetic field at that place will be ( Given tan37∘=43​ )

8×10−5T

6×10−5T

5×10−4T

1×10−4T