The vertex of a parabola is (2,2) and the co-ordinates of its two extrimities of the latus rectum are (-2,0) and (6,0). The equation of the parabola is

Question

The vertex of a parabola is (2,2) and the co-ordinates of its two extrimities of the latus rectum are (-2,0) and (6,0). The equation of the parabola is (A) y 2-4 y +8 x -12=0 (B) x2+4 x-8 y-12=0 (C) x2-4 x+8 y-12=0 (D) x2-8 y-4 x+20=0

Tardigrade Admin · Accepted Answer

Shifting the origin at A equation isX 2=-8 Y now ( x -2)2=-8( y -2) ⇒( C )

Q. The vertex of a parabola is $(2, 2)$ and the co-ordinates of its two extrimities of the latus rectum are $(- 2, 0)$ and $(6, 0)$ . The equation of the parabola is

$y^{2} - 4 y + 8 x - 12 = 0$

$x^{2} + 4 x - 8 y - 12 = 0$

$x^{2} - 4 x + 8 y - 12 = 0$

$x^{2} - 8 y - 4 x + 20 = 0$

Shifting the origin at A equation is $X^{2} = - 8 Y$
now $(x - 2)^{2} = - 8 (y - 2) \Rightarrow (C)$

Q. The vertex of a parabola is (2,2) and the co-ordinates of its two extrimities of the latus rectum are (−2,0) and (6,0). The equation of the parabola is

y2−4y+8x−12=0

x2+4x−8y−12=0

x2−4x+8y−12=0

x2−8y−4x+20=0