The velocity-time graph of a particle of mass 10 kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is

Question

The velocity-time graph of a particle of mass 10 kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-lexz7uqjagqf.png" /> (A) -9300 textJ (B) 12000 textJ (C) -4500 textJ (D) -12000 textJ

Tardigrade Admin · Accepted Answer

v=-5t+50 va t t = 2=40 Δ K . E .=W . D .=(1/2)(402-502) × 10 =-4500 J

Q. The velocity-time graph of a particle of mass $10 k g$ is shown in the figure. The net work done on the particle in the first two seconds of the motion is

$- 9300 J$

$12000 J$

$- 4500 J$

$- 12000 J$

$v = - 5 t + 50$
$v_{a t t = 2} = 40$
$Δ K . E . = W . D . = \frac{1}{2} (4 0^{2} - 5 0^{2}) \times 10$
$= - 4500$ J

Q. The velocity-time graph of a particle of mass 10kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is

−9300J

12000J

−4500J

−12000J