The velocity of the bullet becomes one third after it penetrates 4 cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at (4+ x ) cm inside the block. The value of x is:

Question

The velocity of the bullet becomes one third after it penetrates 4 cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at (4+ x ) cm inside the block. The value of x is: (A) 2.0 (B) 1.0 (C) 0.5 (D) 1.5

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/dba34448840c3ce2021e48c9ee535ec2-.png" /> (( V /3))2- V 2-2 a (4) ⇒ a -(8 V 2/9(8))-( V 2/9) 0= V 2-2 a (4+ x ) ⇒ V 2=2(( V 2/9))(4+ x ) 4.5=4+ x x =0.5

Q. The velocity of the bullet becomes one third after it penetrates $4 c m$ in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at $(4 + x) c m$ inside the block. The value of $x$ is:

$2.0$

$1.0$

$0.5$

$1.5$

$(\frac{V}{3})^{2} - V^{2} - 2 a (4) \Rightarrow a - \frac{8 V ^{2}}{9 ( 8 )} - \frac{V ^{2}}{9}$
$0 = V^{2} - 2 a (4 + x)$
$\Rightarrow V^{2} = 2 (\frac{V ^{2}}{9}) (4 + x)$
$4.5 = 4 + x$
$x = 0.5$

Q. The velocity of the bullet becomes one third after it penetrates 4cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at (4+x)cm inside the block. The value of x is:

2.0

1.0

0.5

1.5