The velocity of sound in a gas. in which two wavelengths 4.08 m and 4.16 m produce 40 beats in 12 s, will be :

Question

The velocity of sound in a gas. in which two wavelengths 4.08 m and 4.16 m produce 40 beats in 12 s, will be : (A) 2.82 .8 ms -1 (B) 175.5 ms -1 (C) 353.6 ms -1 (D) 707.2 ms -1

Tardigrade Admin · Accepted Answer

f b = f 1- f 2 ( v /4.08)-( v /4.16)=(40/12) ⇒ v =707.2

Q. The velocity of sound in a gas. in which two wavelengths $4.08 m$ and $4.16 m$ produce $40$ beats in $12 s$ , will be :

$2.82.8 m s^{- 1}$

$175.5 m s^{- 1}$

$353.6 m s^{- 1}$

$707.2 m s^{- 1}$

$f_{b} = f_{1} - f_{2}$
$\frac{v}{4.08} - \frac{v}{4.16} = \frac{40}{12}$
$\Rightarrow v = 707.2$

Q. The velocity of sound in a gas. in which two wavelengths 4.08m and 4.16m produce 40 beats in 12s, will be :

2.82.8ms−1

175.5ms−1

353.6ms−1

707.2ms−1