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Q. The velocity of sound in a gas. in which two wavelengths $4.08 \,m$ and $4.16 \,m$ produce $40$ beats in $12 \, s$, will be :

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Solution:

$f _{ b }= f _{1}- f _{2}$
$\frac{ v }{4.08}-\frac{ v }{4.16}=\frac{40}{12}$
$\Rightarrow v =707.2$