The velocity of efflux of a liquid through an orific in the bottom of the tank does not depend upon

Question

The velocity of efflux of a liquid through an orific in the bottom of the tank does not depend upon (A) size of orific (B) height of liquid (C) acceleration due to gravity (D) density of liquid

Tardigrade Admin · Accepted Answer

P o +(1/2) ρ text bottom v 2= P o +ρ text liquid g h Velocity of efflux is independent of the size of orifice. The density of the fluid is actually varying with depth for large heights. In such scenarios, velocity of efflux depends on the density of the liquid. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/4591f86d8c1bc34d096576794b5aeac9-.png" />

Q. The velocity of efflux of a liquid through an orific in the bottom of the tank does not depend upon

size of orific

height of liquid

acceleration due to gravity

density of liquid

$P_{o} + \frac{1}{2} ρ_{bottom} v^{2} = P_{o} + ρ_{liquid} g h$
Velocity of efflux is independent of the size of orifice.
The density of the fluid is actually varying with depth for large heights. In such scenarios, velocity of efflux depends on the density of the liquid.

Q. The velocity of efflux of a liquid through an orific in the bottom of the tank does not depend upon

size of orific

height of liquid

acceleration due to gravity

density of liquid

Po​+21​ρbottom ​v2=Po​+ρliquid ​gh Velocity of efflux is independent of the size of orifice. The density of the fluid is actually varying with depth for large heights. In such scenarios, velocity of efflux depends on the density of the liquid.

$P_{o} + \frac{1}{2} ρ_{bottom} v^{2} = P_{o} + ρ_{liquid} g h$
Velocity of efflux is independent of the size of orifice.
The density of the fluid is actually varying with depth for large heights. In such scenarios, velocity of efflux depends on the density of the liquid.