The velocity of a particle is v = v0 + gt + ft2. If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is

Question

The velocity of a particle is v = v0 + gt + ft2. If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is (A) v0 + 2g + 3f (B) v0 + g/2 + f/3 (C) v0 + g + f (D) v0 + g/2 + f

Tardigrade Admin · Accepted Answer

∫ limitsx0dx=∫ limits10(V0+gt+ft2)dt x=v0+g((1/2))+f ((1/3))

Q. The velocity of a particle is $v = v_{0} + g t + f t^{2}$ . If its position is $x = 0$ at $t = 0$ , then its displacement after unit time $(t = 1)$ is

$v_{0} + 2 g + 3 f$

$v_{0} + g /2 + f /3$

$v_{0} + g + f$

$v_{0} + g /2 + f$

$0 \int x d x = 0 \int 1 (V_{0} + g t + f t^{2}) d t$
$x = v_{0} + g (\frac{1}{2}) + f (\frac{1}{3})$

Q. The velocity of a particle is v=v0​+gt+ft2. If its position is x=0 at t=0, then its displacement after unit time (t=1) is

v0​+2g+3f

v0​+g/2+f/3

v0​+g+f

v0​+g/2+f