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  4. The velocity of a particle is v = v0 + gt + ft2. If its position is x = 0 at t = 0, then its displacement after unit time (t = 1) is

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Q. The velocity of a particle is $v = v_0 + gt + ft^2$. If its position is $x = 0$ at $t = 0$, then its displacement after unit time $(t = 1)$ is

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Solution:

$\int\limits^{x}_{{0}}dx=\int\limits^{1}_{{0}}(V_0+gt+ft^2)dt$
$x=v_{0}+g\left(\frac{1}{2}\right)+f \left(\frac{1}{3}\right)$