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Tardigrade
Question
Physics
The velocity of a particle executing SHM varies with displacement (x) as 4 v2=50-x2. The time period of oscillations is (x/7) s. The value of x is (. Take .π=(22/7))
Q. The velocity of a particle executing SHM varies with displacement
(
x
)
as
4
v
2
=
50
−
x
2
. The time period of oscillations is
7
x
s
. The value of
x
is _______
(
Take
π
=
7
22
)
1888
121
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JEE Main 2023
Oscillations
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Answer:
88
Solution:
4
v
2
=
50
−
x
2
⇒
v
=
2
1
50
−
x
2
ω
=
2
1
T
=
ω
2
π
=
4
π
=
7
88
x
=
88