The velocity of a body moving with uniform acceleration at a given instant of time is 10 m / s. After 5 seconds its velocity is 20 m / s. Distance travelled in that time is :

Question

The velocity of a body moving with uniform acceleration at a given instant of time is 10 m / s. After 5 seconds its velocity is 20 m / s. Distance travelled in that time is : (A) 300 m (B) 400 m (C) 150 m (D) 75 m

Tardigrade Admin · Accepted Answer

Here: u=10 m / s, v=20 m / s, t=5 sec From equation of motion, v=u +a t 20=10+a × 5 So, a=2 m / s 2 Now from formula, v2=u2+2 a s 202=102+2 × 2 s so, s=(300/4)=75 m

Q. The velocity of a body moving with uniform acceleration at a given instant of time is $10 m / s$ . After $5$ seconds its velocity is $20 m / s$ . Distance travelled in that time is :

300 m

400 m

150 m

75 m

Here: $u = 10 m / s, v = 20 m / s, t = 5 sec$
From equation of motion, $v = u + a t$
$20 = 10 + a \times 5$ So, $a = 2 m / s^{2}$
Now from formula, $v^{2} = u^{2} + 2 a s$
$2 0^{2} = 1 0^{2} + 2 \times 2 s$
so, $s = \frac{300}{4} = 75 m$

Q. The velocity of a body moving with uniform acceleration at a given instant of time is 10m/s. After 5 seconds its velocity is 20m/s. Distance travelled in that time is :