The variation of velocity of particle executing SHM with time as shown in figure. The velocity of particle when phase change of (π /6) take place:

Question

The variation of velocity of particle executing SHM with time as shown in figure. The velocity of particle when phase change of (π /6) take place: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-x06qt2latt1hkkcq.jpg" /> (A) 3√3ms- 1 (B) 2.5ms- 1 (C) 4.3ms- 1 (D) None

Tardigrade Admin · Accepted Answer

Particle start from E.P. v=v0sinω t v=5sin(.θ .) =5sin(π /6)=(5/2)

Q. The variation of velocity of particle executing $S H M$ with time as shown in figure. The velocity of particle when phase change of $\frac{π}{6}$ take place :

$33 m s^{- 1}$

$2.5 m s^{- 1}$

$4.3 m s^{- 1}$

None

Particle start from E.P.
$v = v_{0} s inω t$
$v = 5 s in (θ)$
$= 5 s in \frac{π}{6} = \frac{5}{2}$

Q. The variation of velocity of particle executing SHM with time as shown in figure. The velocity of particle when phase change of 6π​ take place :

33​ms−1

2.5ms−1

4.3ms−1