Question

The variation of solubility of four different gases $(G1,G2,G3,G4etc.)$ in a given solvent with pressure at a constant temperature is shown in the plot The gas with the highest value of Henry’s law constant is

• A. $G4$
• B. $G2$
• C. $G3$
• D. $G1$

Answer 1

Answer: (D)

According to Henry’s law,
$P=K_{H}X$
where, $K_H$ is Henry’s constant
$\Rightarrow X=\frac{P}{K_H}$
Thus, higher the value of solubility at given pressure, lower will be the value of Henry’s law constant of the gas. As the solubility of $G_1$ is least, thus it will have the highest value of Henry’s law constant.