The variation of electric field along the Z-axis due to a uniformly charged circular ring of radius 'a' in XY plane is shown in the figure. The value of coordinate M will be

Question

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/041ff9f2d02874500a1b6ae8de6aecd8-.png" /> The variation of electric field along the Z-axis due to a uniformly charged circular ring of radius 'a' in XY plane is shown in the figure. The value of coordinate M will be (A) (1/2) (B) √2 (C) 1 (D) (1/√2)

Tardigrade Admin · Accepted Answer

For Ez to be maximum, (d Ez/d z)=0 ∴ z=a / √2 or (Z/a)=(1/√2)

Q.
The variation of electric field along the $Z$ -axis due to a uniformly charged circular ring of radius ' $a$ ' in $X Y$ plane is shown in the figure. The value of coordinate $M$ will be

$\frac{1}{2}$

$2$

$1$

$\frac{1}{2}$

For $E_{z}$ to be maximum,
$\frac{d E _{z}}{d z} = 0$
$∴ z = a / 2$ or $\frac{Z}{a} = \frac{1}{2}$

Q. The variation of electric field along the Z-axis due to a uniformly charged circular ring of radius 'a' in XY plane is shown in the figure. The value of coordinate M will be

21​

2​

1

2​1​

For Ez​ to be maximum, dzdEz​​=0 ∴z=a/2​ or aZ​=2​1​

Q.
The variation of electric field along the $Z$ -axis due to a uniformly charged circular ring of radius ' $a$ ' in $X Y$ plane is shown in the figure. The value of coordinate $M$ will be

$\frac{1}{2}$

$2$

$1$

$\frac{1}{2}$

For $E_{z}$ to be maximum,
$\frac{d E _{z}}{d z} = 0$
$∴ z = a / 2$ or $\frac{Z}{a} = \frac{1}{2}$