The variation of density of a solid with temperature is given by the formula

Question

The variation of density of a solid with temperature is given by the formula (A) d2=(d1/1+&gamma;(t2-t1)) (B) d2=(d1/1-&gamma;(t2-t1)) (C) d2=(d1/1-2&gamma;(t2-t1)) (D) d2=(d1/1+2&gamma;(t2-t1))

Tardigrade Admin · Accepted Answer

From the definition of &gamma;, we know it is defined as change in volume per volume per unit temperature difference. So, &gamma;=( V 2- V 1/ V 1( t 2- t 1)) Or V 2= V 1[1+&gamma;( t 2- t 1)] Now, density = mass/ volume, So, replacing V 1 with ( M / d 1) and V 2 with ( M / d 2) we have, d 2=( d 1/[1+&gamma;( t 2- t 1)])

Q. The variation of density of a solid with temperature is given by the formula

$d_{2} = \frac{d _{1}}{1 + γ ( t _{2} - t _{1} )}$

$d_{2} = \frac{d _{1}}{1 - γ ( t _{2} - t _{1} )}$

$d_{2} = \frac{d _{1}}{1 - 2 γ ( t _{2} - t _{1} )}$

$d_{2} = \frac{d _{1}}{1 + 2 γ ( t _{2} - t _{1} )}$

Q. The variation of density of a solid with temperature is given by the formula

d2​=1+γ(t2​−t1​)d1​​

d2​=1−γ(t2​−t1​)d1​​

d2​=1−2γ(t2​−t1​)d1​​

d2​=1+2γ(t2​−t1​)d1​​

$d_{2} = \frac{d _{1}}{1 + γ ( t _{2} - t _{1} )}$

$d_{2} = \frac{d _{1}}{1 - γ ( t _{2} - t _{1} )}$

$d_{2} = \frac{d _{1}}{1 - 2 γ ( t _{2} - t _{1} )}$

$d_{2} = \frac{d _{1}}{1 + 2 γ ( t _{2} - t _{1} )}$