Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The variance of first 50 even natural numbers is
Q. The variance of first
50
even natural numbers is
1995
271
JEE Main
JEE Main 2014
Statistics
Report Error
A
4
833
24%
B
833
49%
C
437
16%
D
4
437
11%
Solution:
Variance
=
N
Σ
x
i
2
−
(
x
ˉ
)
2
σ
2
=
50
2
2
+
4
2
+
…
+
10
0
2
−
(
50
2
+
4
+
…
+
100
)
2
=
50
4
(
1
2
+
2
2
+
3
2
+
…
.
+
5
0
2
)
−
(
51
)
2
=
4
(
50
×
6
50
×
51
×
101
)
−
(
51
)
2
=
3434
−
2601
⇒
σ
2
=
833