The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to

Question

The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to (A) 2.39 mm Hg (B) 2.42 mm Hg (C) 21.42 mm Hg (D) 21.44 mm Hg

Tardigrade Admin · Accepted Answer

Δ P = p° × xB = 23.8 × 0.1 = 2.38 ∴ Vapour pressure of sol. = 23.8 - 2.38 = 21.42 mm Hg.

Q. The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to

2.39 mm Hg

2.42 mm Hg

21.42 mm Hg

21.44 mm Hg

$Δ P = p^{\circ} \times x_{B} = 23.8 \times 0.1 = 2.38$
$∴$ Vapour pressure of sol. = 23.8 - 2.38
= 21.42 mm Hg.

Q. The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to

2.39 mm Hg

2.42 mm Hg

21.42 mm Hg

21.44 mm Hg

ΔP=p∘×xB​=23.8×0.1=2.38 ∴ Vapour pressure of sol. = 23.8 - 2.38 = 21.42 mm Hg.

$Δ P = p^{\circ} \times x_{B} = 23.8 \times 0.1 = 2.38$
$∴$ Vapour pressure of sol. = 23.8 - 2.38
= 21.42 mm Hg.