The vapour pressure of water at 80°C is 355.5 mm Hg. A 100 mL vessel contains water saturated with O2 at 80°C, the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50 mL vessel at the same temperature. What is the partial pressure of O2?

Question

The vapour pressure of water at 80°C is 355.5 mm Hg. A 100 mL vessel contains water saturated with O2 at 80°C, the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50 mL vessel at the same temperature. What is the partial pressure of O2? (A) 1115 mm (B) 809 mm (C) 405 mm (D) 3555 mm

Tardigrade Admin · Accepted Answer

p textTotal = pH2O + pO2 pH2O = 760 -355.5 = 404.5 mm Hg When the contents were pumped into 50 mL vessel p1 - 404.5 mm Hg, V1 = 100 mL, p2 = ? V2 = 50 mL P1V1 =P2V2 p2 = (404.5 × 100/50) = 809 Thus, pO2 in 50 mL vessel = 809 mm Hg

$1115$ mm

$809$ mm

$405$ mm

$3555$ mm

Q. The vapour pressure of water at 80∘C is 355.5 mm Hg.A100mL vessel contains water saturated with O2​ at 80∘C, the total pressure being 760 mm of Hg. The contents of the vessel were pumped into a 50mL vessel at the same temperature. What is the partial pressure of O2​?

1115 mm

809 mm

405 mm

3555 mm

pTotal​=pH2​O​+pO2​​ pH2​O​=760−355.5=404.5mmHg When the contents were pumped into 50mL vessel p1​−404.5mmHg, V1​=100mL,p2​=?V2​=50mL P1​V1​=P2​V2​ p2​=50404.5×100​=809 Thus, pO2​​ in 50mL vessel = 809mmHg

$1115$ mm

$809$ mm

$405$ mm

$3555$ mm