The vapour pressure of pure water at 26° C is 25.5 torr.. The vapour pressure of a solution which contains 20.0 glucose, ( C 6 H 12 O 6), in 100 g water (in torr) is? (report the answer by rounding off to the nearest integer)

Question

The vapour pressure of pure water at 26° C is 25.5 torr.. The vapour pressure of a solution which contains 20.0 glucose, ( C 6 H 12 O 6), in 100 g water (in torr) is? (report the answer by rounding off to the nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Using Roult's law equation ( P A 0- P A / P A 0)=( n B / n A + n B ) Or ( P A 0- P A / P A )=( n B / n A ) P A = the vapour pressure of the pure solution P A 0= the vapour pressure of the pure component n B : moles of solute n A : moles of solvent ( P A 0- P A / P A )=( n B / n A ) (25.5- P A / P A )=((20/180)/(100)18) (25.5- P A / P A )=(20 × 18/100 × 180)=0.02 25.5- P A =0.02 P A 1.02 P A =25.5 P A =25.0

Q. The vapour pressure of pure water at 26∘C is 25.5 torr.. The vapour pressure of a solution which contains 20.0 glucose, (C6​H12​O6​), in 100g water (in torr) is? (report the answer by rounding off to the nearest integer)

Q. The vapour pressure of pure water at $2 6^{\circ} C$ is $25.5$ torr.. The vapour pressure of a solution which contains $20.0$ glucose, $(C_{6} H_{12} O_{6})$ , in $100 g$ water (in torr) is? (report the answer by rounding off to the nearest integer)