The vapour density of PCl5 is 104.25 but when heated to 230°C, its vapour density is reduced to 62. The degree of dissociation of PCl5 at this temperature will be

Question

The vapour density of PCl5 is 104.25 but when heated to 230°C, its vapour density is reduced to 62. The degree of dissociation of PCl5 at this temperature will be (A) 6.8 % (B) 6 8 % (C) 46 % (D) 64 %

Tardigrade Admin · Accepted Answer

PCl5(g) leftharpoons PCl3 +Cl2 (g) 1+α =(104.25/62) 1+α=1.68 ∴ α=0.68 or 68 %

Q. The vapour density of $PC l_{5}$ is $104.25$ but when heated to $230° C$ , its vapour density is reduced to $62.$ The degree of dissociation of $PC l_{5}$ at this temperature will be

$6.8%$

$68%$

$46%$

$64%$

$PC l_{5} (g) ⇌ PC l_{3} + C l_{2} (g)$
$1 + α = \frac{104.25}{62} 1 + α = 1.68$
$∴ α = 0.68 or 68%$

Q. The vapour density of PCl5​ is 104.25 but when heated to 230°C, its vapour density is reduced to 62. The degree of dissociation of PCl5​ at this temperature will be

6.8%

68%

46%

64%