The vapour density of N2O4 at a certain temperature is 30. What is the percentage dissociation of N2O4 at this temperature ?

Question

The vapour density of N2O4 at a certain temperature is 30. What is the percentage dissociation of N2O4 at this temperature ? (A) 53.3% (B) 106.6% (C) 26.7% (D) None.

Tardigrade Admin · Accepted Answer

Mol. wt. of N2O4 = 92 Vapour density, D = (92/2) = 46 N2O4(g) leftharpoons 2NO2(g) Here y = 2 d = 30 x = (D-d/d(y-1)) = 0.533 = 53.3 %

Q. The vapour density of $N_{2} O_{4}$ at a certain temperature is 30. What is the percentage dissociation of $N_{2} O_{4}$ at this temperature ?

53.3%

106.6%

26.7%

None.

Mol. wt. of $N_{2} O_{4}$ = 92
Vapour density, D = $\frac{92}{2}$ = 46
$N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)$
Here $y = 2$
$d = 30$
$x = \frac{D - d}{d ( y - 1 )}$ = 0.533 = 53.3 %

Q. The vapour density of N2​O4​ at a certain temperature is 30. What is the percentage dissociation of N2​O4​ at this temperature ?