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Q. The vapour density of $N_2O_4$ at a certain temperature is 30. What is the percentage dissociation of $N_2O_4$ at this temperature ?

Equilibrium

Solution:

Mol. wt. of $N_2O_4$ = 92
Vapour density, D = $\frac{92}{2}$ = 46
$N_2O_4(g) \rightleftharpoons 2NO_2(g)$
Here $y = 2$
$d = 30$
$x = \frac{D-d}{d(y-1)}$ = 0.533 = 53.3 %