The vapour density of a gas A is twice that of a gas B. If the molecular weight of B is M, the molecular weight of A will be:

Question

The vapour density of a gas A is twice that of a gas B. If the molecular weight of B is M, the molecular weight of A will be: (A) M (B) 2 M (C) 3 M (D) (M/2)

Tardigrade Admin · Accepted Answer

( textVapour density of A/ textVapour density of B)=( textmolar mass of A/ textmolar mass of B) Molar mass of A =2×(M/1)

Q. The vapour density of a gas $A$ is twice that of a gas $B$ . If the molecular weight of $B$ is $M$ , the molecular weight of $A$ will be:

$M$

$2 M$

$3 M$

$\frac{M}{2}$

$\frac{Vapour density of A}{Vapour density of B} = \frac{molar mass of A}{molar mass of B}$
Molar mass of $A = 2 \times \frac{M}{1}$

Q. The vapour density of a gas A is twice that of a gas B. If the molecular weight of B is M, the molecular weight of A will be:

M

2M

3M

2M​

Vapour density ofBVapour density ofA​=molar mass ofBmolar mass ofA​ Molar mass of A=2×1M​

Q. The vapour density of a gas $A$ is twice that of a gas $B$ . If the molecular weight of $B$ is $M$ , the molecular weight of $A$ will be:

$M$

$2 M$

$3 M$

$\frac{M}{2}$

$\frac{Vapour density of A}{Vapour density of B} = \frac{molar mass of A}{molar mass of B}$
Molar mass of $A = 2 \times \frac{M}{1}$