Question

The van’t Hoff factor of $0.005M$ aqueous solution of $KCl$ is $1.95$. The degree of ionisation of $KCl$ is

• A. $0.95$
• B. $0.97$
• C. $0.94$
• D. $0.96$

Answer 1

Answer: (A)

$KCl\rightleftharpoons K^{+}+C{l}^{-}\left(n=2\right)$
$\alpha =\frac{i-1}{n-1}=\frac{1.95-1}{2-1}=0.95$