Question

The van't Hoff factor for $0.01m{K}_{2}S{O}_4$ solution is $2.70$. The degree of dissociation is________ $\%$

Answer 1

Answer: 85

For $K_{2}S{O}_4,i=2.70$
$n^{\prime }=3$
Degree of dissociation $(\alpha )=\frac{i-1}{n^{\prime }-1}$
$=\frac{2.70-1}{3-1}=0.85$
$\therefore$ Percentage degree of dissociation $=85\%$