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Q. The van't Hoff factor for $0.01\, m\, K _{2} SO _{4}$ solution is $2.70$. The degree of dissociation is________ $\%$

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Solution:

For $K _{2} SO _{4}, i=2.70$
$n'=3$
Degree of dissociation $(\alpha)=\frac{i-1}{ n'-1}$
$=\frac{2.70-1}{3-1}=0.85$
$\therefore $ Percentage degree of dissociation $=85 \%$